Integrand size = 23, antiderivative size = 73 \[ \int \frac {(1+2 \sin (c+d x))^2}{\sin ^{\frac {6}{5}}(c+d x)} \, dx=-\frac {5 \cos (c+d x)}{d \sqrt [5]{\sin (c+d x)}}+\frac {5 \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {2}{5},\frac {1}{2},\frac {7}{5},\sin ^2(c+d x)\right ) \sin ^{\frac {4}{5}}(c+d x)}{d \sqrt {\cos ^2(c+d x)}} \]
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Time = 0.06 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {2868, 2722, 3090} \[ \int \frac {(1+2 \sin (c+d x))^2}{\sin ^{\frac {6}{5}}(c+d x)} \, dx=\frac {5 \sin ^{\frac {4}{5}}(c+d x) \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {2}{5},\frac {1}{2},\frac {7}{5},\sin ^2(c+d x)\right )}{d \sqrt {\cos ^2(c+d x)}}-\frac {5 \cos (c+d x)}{d \sqrt [5]{\sin (c+d x)}} \]
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Rule 2722
Rule 2868
Rule 3090
Rubi steps \begin{align*} \text {integral}& = 4 \int \frac {1}{\sqrt [5]{\sin (c+d x)}} \, dx+\int \frac {1+4 \sin ^2(c+d x)}{\sin ^{\frac {6}{5}}(c+d x)} \, dx \\ & = -\frac {5 \cos (c+d x)}{d \sqrt [5]{\sin (c+d x)}}+\frac {5 \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {2}{5},\frac {1}{2},\frac {7}{5},\sin ^2(c+d x)\right ) \sin ^{\frac {4}{5}}(c+d x)}{d \sqrt {\cos ^2(c+d x)}} \\ \end{align*}
Time = 0.19 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.51 \[ \int \frac {(1+2 \sin (c+d x))^2}{\sin ^{\frac {6}{5}}(c+d x)} \, dx=\frac {5 \sqrt {\cos ^2(c+d x)} \sec (c+d x) \left (-9 \operatorname {Hypergeometric2F1}\left (-\frac {1}{10},\frac {1}{2},\frac {9}{10},\sin ^2(c+d x)\right )+\sin (c+d x) \left (9 \operatorname {Hypergeometric2F1}\left (\frac {2}{5},\frac {1}{2},\frac {7}{5},\sin ^2(c+d x)\right )+4 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {9}{10},\frac {19}{10},\sin ^2(c+d x)\right ) \sin (c+d x)\right )\right )}{9 d \sqrt [5]{\sin (c+d x)}} \]
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\[\int \frac {\left (2 \sin \left (d x +c \right )+1\right )^{2}}{\sin \left (d x +c \right )^{\frac {6}{5}}}d x\]
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\[ \int \frac {(1+2 \sin (c+d x))^2}{\sin ^{\frac {6}{5}}(c+d x)} \, dx=\int { \frac {{\left (2 \, \sin \left (d x + c\right ) + 1\right )}^{2}}{\sin \left (d x + c\right )^{\frac {6}{5}}} \,d x } \]
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Timed out. \[ \int \frac {(1+2 \sin (c+d x))^2}{\sin ^{\frac {6}{5}}(c+d x)} \, dx=\text {Timed out} \]
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\[ \int \frac {(1+2 \sin (c+d x))^2}{\sin ^{\frac {6}{5}}(c+d x)} \, dx=\int { \frac {{\left (2 \, \sin \left (d x + c\right ) + 1\right )}^{2}}{\sin \left (d x + c\right )^{\frac {6}{5}}} \,d x } \]
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\[ \int \frac {(1+2 \sin (c+d x))^2}{\sin ^{\frac {6}{5}}(c+d x)} \, dx=\int { \frac {{\left (2 \, \sin \left (d x + c\right ) + 1\right )}^{2}}{\sin \left (d x + c\right )^{\frac {6}{5}}} \,d x } \]
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Time = 6.98 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.74 \[ \int \frac {(1+2 \sin (c+d x))^2}{\sin ^{\frac {6}{5}}(c+d x)} \, dx=-\frac {4\,\cos \left (c+d\,x\right )\,{\sin \left (c+d\,x\right )}^{4/5}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {3}{5};\ \frac {3}{2};\ {\cos \left (c+d\,x\right )}^2\right )}{d\,{\left ({\sin \left (c+d\,x\right )}^2\right )}^{2/5}}-\frac {\cos \left (c+d\,x\right )\,{\left ({\sin \left (c+d\,x\right )}^2\right )}^{1/10}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {11}{10};\ \frac {3}{2};\ {\cos \left (c+d\,x\right )}^2\right )}{d\,{\sin \left (c+d\,x\right )}^{1/5}}-\frac {4\,\cos \left (c+d\,x\right )\,{\sin \left (c+d\,x\right )}^{9/5}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{10},\frac {1}{2};\ \frac {3}{2};\ {\cos \left (c+d\,x\right )}^2\right )}{d\,{\left ({\sin \left (c+d\,x\right )}^2\right )}^{9/10}} \]
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